8th Grade > Mathematics
PRACTICAL GEOMETRY MCQs
Total Questions : 56
| Page 2 of 6 pages
Answer: Option D. -> No, it is impossible
:
D
Step1: Draw rough diagram of the parallelogram ABCD
Here, ∠DAC = ∠ ACB= 15∘ - (1) (Alternate interior angles)
In △ABC,
∠ A + ∠ B + ∠ C must be 180∘
∠ A + ∠ B + ∠ C = 25∘ + 110∘ + 15∘ (from (1))
∠ A + ∠ B + ∠ C = 150∘
The sum of angles in a triangle should always be equal to 180∘. So, this construction is not possible.
:
D
Step1: Draw rough diagram of the parallelogram ABCD
Here, ∠DAC = ∠ ACB= 15∘ - (1) (Alternate interior angles)
In △ABC,
∠ A + ∠ B + ∠ C must be 180∘
∠ A + ∠ B + ∠ C = 25∘ + 110∘ + 15∘ (from (1))
∠ A + ∠ B + ∠ C = 150∘
The sum of angles in a triangle should always be equal to 180∘. So, this construction is not possible.
Answer: Option C. -> With 3 sides, Yes; With 3 angles, No
:
C
Measurement of all the sides or 2 angles and 1 side or 1 angle and 2 sides are required to construct auniquetriangle. Using 3 angles, we can construct many triangles, not a unique triangle. For e.g. there are infinite equilateral triangles though they have all the angles equal to 60∘.
:
C
Measurement of all the sides or 2 angles and 1 side or 1 angle and 2 sides are required to construct auniquetriangle. Using 3 angles, we can construct many triangles, not a unique triangle. For e.g. there are infinite equilateral triangles though they have all the angles equal to 60∘.
Answer: Option C. -> 6
:
C
Since one side of a triangle cannot be greater than thesum of the other two sides, diagonal LY must be smaller than the sum of PL + PY and smaller than the sum of AL + AY. PL + PY =5 and AL + AY = 8.5. Hence, LY must be lessthan 5. Thus, the correct answer is 6.
:
C
Since one side of a triangle cannot be greater than thesum of the other two sides, diagonal LY must be smaller than the sum of PL + PY and smaller than the sum of AL + AY. PL + PY =5 and AL + AY = 8.5. Hence, LY must be lessthan 5. Thus, the correct answer is 6.
Answer: Option A. -> Compass
:
A
To make the two line segments meet, arcs are drawn and their intersection point is found. A compass is hence used.
:
A
To make the two line segments meet, arcs are drawn and their intersection point is found. A compass is hence used.
Answer: Option B. -> Protractor
:
B
3 sides and 2 diagonalsof a quadrilateralis known. This information is enough to construct a quadrilateral. Thus, a protractor is not necessary for the construction because no angles are measured or drawn during construction.
:
B
3 sides and 2 diagonalsof a quadrilateralis known. This information is enough to construct a quadrilateral. Thus, a protractor is not necessary for the construction because no angles are measured or drawn during construction.
Answer: Option C. -> 3
:
C
To construct a parallelogram both unequal sides need to be provided. Other than this one angle or one diagonal should be provided. Hence, a minimum of 3 measurements are needed.
:
C
To construct a parallelogram both unequal sides need to be provided. Other than this one angle or one diagonal should be provided. Hence, a minimum of 3 measurements are needed.
Answer: Option A. -> True
:
A
As all the sides are equal and all the angles measure 90 degrees in a square, the given information is enough to construct a square.
:
A
As all the sides are equal and all the angles measure 90 degrees in a square, the given information is enough to construct a square.
Answer: Option B. -> Line Segment
:
B
Drawing a line segment, which lies in between two given angles, is the first step in this construction. After the line segment is constructed, angles are drawn using that line segment as the base.
:
B
Drawing a line segment, which lies in between two given angles, is the first step in this construction. After the line segment is constructed, angles are drawn using that line segment as the base.
Answer: Option B. -> 2
:
B
To construct a quadrilateral, we need to construct two triangles. As, both the diagonals are known, we can construct any of the two triangles first. Thus, there are two ways to start this construction.
:
B
To construct a quadrilateral, we need to construct two triangles. As, both the diagonals are known, we can construct any of the two triangles first. Thus, there are two ways to start this construction.
Answer: Option A. -> 1
:
A
Sum of the two sides of the triangle is greater than 3rd side
let, 1st side be a=2, 2nd be b=3, 3rd be c.
As per above condition,
a+b>c ⇒ 2+3>c⇒ c<5
a+c>b ⇒ 2+c>3⇒ c>1
so,1<c<5units
:
A
Sum of the two sides of the triangle is greater than 3rd side
let, 1st side be a=2, 2nd be b=3, 3rd be c.
As per above condition,
a+b>c ⇒ 2+3>c⇒ c<5
a+c>b ⇒ 2+c>3⇒ c>1
so,1<c<5units
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