7th Grade > Mathematics
PRACTICAL GEOMETRY MCQs
:
A, B, and C
If two lines are parallel then:
Corresponding angles are equal i.e., ∠a=∠e
Alternate interior angles are equal i.e., ∠c=∠f
Alternate exterior angles are equal i.e., ∠b=∠g
Vertically opposite angles are equal in case of intersecting lines.
Two angles are complementary when they add up to 90 degrees.
:
C
Statement 2 is correct while statement 1 is incorrect.
Reason:-If the lines are perpendicular to each other, then the pair of vertically opposite angles are also supplementary.
:
The condition to form a triangle is that sum of the lengths of two sides of a triangle must be greater than the third one.
Consider 3 cm , 7 cm and 14 cm ;
3 + 7 ≯ 14 cm
Similarily if we consider other combination 7 ,14 ,21 , 14 + 21 ≯ 7
Hence no triangles can be formed.
:
D
If the lengths of the two sides enclosing the right angle in a right-angled triangle are given, we do not require any more data to draw the triangle.
:
A and C
When all the angles of a triangle are given, then you won't be able to draw a unique triangle. To get a unique triangle at least one side of a triangle should be given.
When two side and included angle is given then, then any unique triangle can be drawn.
Similarily in case of two angles and an included side, a unique triangle can be drawn.
:
As stated in question line segment BD is angle bisector so, ∠ABD=∠DBC
And, ∠ABD+∠DBC=∠ABC
So,∠(ABC)=2∠(ABD)
:
The sum of any two sides of a triangle is greater than the third side.
Here, 7cm+3cm=10cm, which is less than 14cm. So, a triangle can't be constructed.
Therefore, Akash will not get the arcs intersecting at any point.
:
When a line segment is perpendicular to another line segment then angle between them is 90o.
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A
If two lines are parallel to each other, then the corresponding angles formed when a transversal passes through them are equal. By the converse of the previous statement, if the corresponding angles are equal, then the lines must be parallel. So, Pavan's conclusion is true.