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8th Grade > Mathematics

PLAYING WITH NUMBERS MCQs

Total Questions : 54 | Page 4 of 6 pages
Question 31.


Which of the following is not divisible by 2?


  1.     123123
  2.     34567896
  3.     2345678234
  4.     18322
 Discuss Question
Answer: Option A. -> 123123
:
A

All the even numbers and the numbers ending with 0 are divisible by 2.
Among the given options, 123123 has its last digit as 3 which makes it an odd number. Hence, this number is not divisible by 2.


Question 32.


Which of the following numbers is not divisible by 5?


  1.     12345
  2.     1234560
  3.     1232
  4.     1230
 Discuss Question
Answer: Option C. -> 1232
:
C

The numbers 12345, 1230 and 1234560 have last digits as 5, 0 and 0 respectively. Hence, all three numbers are divisible by 5.
On the other hand, 1232 ends with a number other than 0 or 5. Hence, it is not divisible by 5.


Question 33.


Find the values of A and B    1 2 A+ 6 A B   A 0 9


  1.     A = 8, B = 1
  2.     A = 1, B = 8
  3.     A = 9, B = 3
  4.     A = 3, B = 9
 Discuss Question
Answer: Option A. -> A = 8, B = 1
:
A

We know that A + 2 is a two digit number with unit digit as 0. So, A = 8


A + B is a single digit number and is equal to 9. 
A + B = 9
       B = 9 - A
       B = 9 - 8 = 1
Therefore, A = 8 and B = 1
   1 2 8+ 6 8 1   8 0 9


Question 34.


The usual form of 100×7+10×5+6 is 


___
 Discuss Question
Answer: Option A. -> A = 8, B = 1
:

100×7+10×5+6=700+50+6=756


Question 35.


123 can be expressed as:


  1.     10×1+10×2+10×3
     
  2.     100×1+100×2+100×3
     
  3.     100×1+10×2+1×3
     
  4.     1×1+1×2+1×3
 Discuss Question
Answer: Option C. -> 100×1+10×2+1×3
 

:
C

Let the number be abc.
Then the general form of abc will be:

100×a+10×b+1×c
Thus, 123=(100×1)+(10×2)+(1×3)


Question 36.


1000×2+100×3+10×2+1×4  is expressed as:


  1.     4232
  2.     1111
  3.     2024
  4.     2324
 Discuss Question
Answer: Option D. -> 2324
:
D

1000×2+100×3+10×2+1×4=2000+300+20+4=2324.


Question 37.


Aarush asked Soham to take any 2 or 3 digit number and reverse the digits, then subtract the larger number from the smaller number. Soham did the same and concluded that the result is exactly divisible by 9. What Soham concluded is:


  1.     True
  2.     False
  3.     2024
  4.     2324
 Discuss Question
Answer: Option A. -> True
:
A

Let's consider a two digit number ab.Its general form will be 10×a+1×b.
If we reverse the digits, its general form will be 10×b+1×a. If we subtract both of the numbers, we get:
 (10×a+1×b)(10×b+1×a)
= (10a + b) -  (10b + a)
= 10a  + b  -10b - a
= 9a - 9b
= 9 (a-b)
Observe that the result is a multiple of 9 and hence is exactly divisible by 9.
Similarly, for 3 digit numbers, the difference of the number and number obtained by reversing the digits (if abc is the number) will be given by:
(100×a+10×b+c)(100×c+10×b+a)
=100a + 10b + c - (100c + 10b + a)
= 100a + 10b + c - 100c - 10b - a
= 99a - 99c
= 99 (a-c)
= 9×11(ac) 
which is also divisible by 9.
Note that this happens with any 2 or 3 number.


Question 38.


When Rashi ordered pizza and coke, the bill had the digits A and B not visible clearly.


Pizza           A12Coke       + 31B                     525


Using the information visible on her bill, find the digits A and B respectively.


  1.     A = 2, B = 1
  2.     A = 3, B = 5
  3.     A = 1, B = 3
  4.     A = 2, B = 3
 Discuss Question
Answer: Option D. -> A = 2, B = 3
:
D

In the tens place, the numbers being added are 1 and 1. The sum given in the tens place is 2, which means there is no carry over throughout the summation.
A + 3 = 5 i.e A = 5 - 3 = 2  and


2 + B = 5 i.e B = 5 - 2 = 3
 


Pizza           212Coke       + 313                     525


Question 39.


Soham borrowed money from his mother for  buying pens. He bought 7 pens and the price of each pen is a two digit number, 1A. If the total amount spent by him is 10A, then the value of A is 


___
 Discuss Question
Answer: Option D. -> A = 2, B = 3
:

Price of one Pen =1×10+A


Number of Pens = 7


Total price =(10+A)×7


(10+A)×7=(100+A)


70 + 7A = 100 + A


6A = 30


A = 5


Question 40.


By which of the following numbers is 392 divisible?


  1.     9
  2.     3
  3.     2
  4.     4
 Discuss Question
Answer: Option C. -> 2
:
C and D

A number is divisible by 3 or 9 if the sum of its digits is divisible by 3 or 9 respectively.
Here, sum of digits = 3 + 9 + 2 = 14 which is not divisible by either 3 or 9. Hence, the number is not divisible by 3 and 9.
Being an even number, the given number is divisible by 2.
A number is divisible by 4 if the number formed by the last two digits are divisible by 4.
In 392, 92 which is divisible by 4. Hence, the number is also divisible by 4.


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