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8th Grade > Mathematics

PLAYING WITH NUMBERS MCQs

Total Questions : 54 | Page 2 of 6 pages
Question 11. Which of the following is not divisible by 2?
  1.    123123
  2.    34567896
  3.    2345678234
  4.    18322
 Discuss Question
Answer: Option A. -> 123123
:
A
All the even numbers and the numbers ending with 0 are divisible by 2.
Among the given options,123123 has its last digit as 3 which makes it an odd number.Hence, this number is not divisible by 2.
Question 12. 1000×2+100×3+10×2+1×4  is expressed as:
  1.    4232
  2.    1111
  3.    2024
  4.    2324
 Discuss Question
Answer: Option D. -> 2324
:
D
1000×2+100×3+10×2+1×4=2000+300+20+4=2324.
Question 13. Soham got a call from Manish who was not very clear with the concepts of divisibility. Manish then asked, "Is 244 divisible by 2?” . Soham replied yes. Is Soham's reply true or false?
  1.    True
  2.    False
  3.    8
  4.    6
 Discuss Question
Answer: Option A. -> True
:
A
Ifthe ones digit of a number is 0, 2, 4, 6 or 8 then the number is divisible by 2.
For the number 244 in the ones place we find 4 which is divisible by 2. Therefore we can say that the number 244 is divisible by 2.
Question 14. When Rashi ordered pizza and coke, the bill had the digits A and B not visible clearly.
Pizza           A12Coke       + 31B                     525
Using the information visible on her bill, find the digits A and B respectively.
  1.    A = 2, B = 1
  2.    A = 3, B = 5
  3.    A = 1, B = 3
  4.    A = 2, B = 3
 Discuss Question
Answer: Option D. -> A = 2, B = 3
:
D
In the tens place, the numbers being added are 1 and 1. The sum given in the tens place is2, which means there is no carry over throughout the summation.
A + 3 = 5 i.e A = 5 - 3 = 2 and

2 + B = 5 i.e B = 5 - 2 = 3
Pizza212Coke+313525
Question 15. Find Q in the addition
   3 1 Q+ 1 Q 3   5 0 1
  1.    1
  2.    4
  3.    5
  4.    8
 Discuss Question
Answer: Option D. -> 8
:
D
Study the addition in the ones column:
Q + 3 = 1,a number whose ones digit is 1.
If Q = 8, then 8 + 3 = 11.
So, the puzzle can be solved as shown below:
318+183501
Hence, Q = 8
Question 16. Soham borrowed money from his mother for  buying pens. He bought 7 pens and the price of each pen is a two digit number, 1A. If the total amount spent by him is 10A, then the value of A is 
___
 Discuss Question

:
Price of one Pen =1×10+A
Number of Pens = 7
Total price =(10+A)×7
(10+A)×7=(100+A)
70 + 7A = 100 + A
6A = 30
A = 5
Question 17. Aarush asked Soham to take any 2 or 3 digit number and reverse the digits, then subtract the larger number from the smaller number. Soham did the same and concluded that the result is exactly divisible by 9. What Soham concluded is:
  1.    True
  2.    False
  3.    2024
  4.    2324
 Discuss Question
Answer: Option A. -> True
:
A
Let's considera two digitnumber ab.Its general form will be 10×a+1×b.
If wereverse the digits, its general form will be 10×b+1×a. If we subtract both of the numbers, we get:
(10×a+1×b)(10×b+1×a)
= (10a + b) - (10b + a)
= 10a + b -10b - a
= 9a - 9b
= 9 (a-b)
Observe that the result is a multiple of 9 and hence is exactly divisible by 9.
Similarly, for 3 digit numbers, the difference of the number and number obtained by reversing the digits (if abc is the number) will be given by:
(100×a+10×b+c)(100×c+10×b+a)
=100a + 10b + c - (100c + 10b + a)
= 100a + 10b + c - 100c - 10b - a
= 99a - 99c
= 99 (a-c)
= 9×11(ac)
which is also divisible by 9.
Note that this happens with any 2 or 3number.
Question 18. I take a 3 digit number with distinct digits. I can get 6 different 3 digit numbers by rearranging the digits of this number.
  1.    True
  2.    False
  3.    50
  4.    51
 Discuss Question
Answer: Option A. -> True
:
A
Let the3 digit number beabc.On rearrangingthedigits I get, abc, bac, cba, cab, acb, bca. Hence Iwill get 6 three digit numbers.
Question 19. What is the remainder when 1591 is divided by 1000?
  1.    91
  2.    0
  3.    591
  4.    1
 Discuss Question
Answer: Option C. -> 591
:
C
On dividing 1591 by 1000, the remainder is the last 3 digits. Hence it is 591.
Question 20. (f × 100) + (d × 10) + e is written as
  1.    def
  2.    efd
  3.    fde
  4.    edf
 Discuss Question
Answer: Option C. -> fde
:
C
(f×100) + (d×10) + e is written asfde which is a three digit number.
For example, (2 × 100) + (3 × 10) + 1 is the expanded form of 231.

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