Exams > Bitsat
PHYSICS MCQs
A force of constant magnitude which is always perpendicular to the velocity of the particle does not do work . Hence , K.E. of the particle is constant . As force is perpendicular to the velocity the particle moves in a circular path
Since cage is closed , external force on the system remains constant . Hence , the boy will feel the weight of cage as unchanged.
`tan (90^circ - theta) = 20/15`
`:.` ` cot theta = 20/15` = `4/3`
`rArr theta = 37^circ`
`:.` `alpha = 37^circ + 23^circ` = `60^circ`
Let the distance between spots A and B is `l`.
`u`= speed of river stream
`v` = speed of motor boat in still water
During downstream ,
`t_1 = (l)/(v + u)`.........................................................(i)
Similarly in upstream
`t_2 = (l)/(v - u)`.....................................................(ii)
In still water , `t = l/v` .........................................................(iii)
After solving equation (i), (ii) and (iii) , we get .
`t `= 9.6 hour.
Since the condition of (C) is no given .
Hence , man may cross the river along shortest path.