Perimeter of square = 4 * Side

=>Side = 56/4  =  14cm.

Perimeter of rectangle  = 56/2  = 28cm

Breadth = 28/2 - 9 = 5 cm

Required difference = 14- 5 = 9cm

(533 + 128 + 429 + 225 + x + 305 + 601 + 804)/8 = 474

=> 3025 + x = 8 * 474

=> x = 3792 - 3025 = 767

Perimeter of square = Distance covered by man in 80 seconds = (39.6 * 5/18  * 18) metre

= 880 metre

Side of square = 880/4 = 220

Area of square = 220 * 220 = 48400 sq.metre

Time taken by truck = Distance/Speed  = 256/32  =  8 hours

Distance covered by car in 8 hours = 256 + 160 = 416 km

Average speed of car = 416/8 = 52 kmph

Total marks obtained by Sushil = 103 + 111 + 98 + 110 + 88

= 510

Total maximum marks = x (let)

(x * 85)/100 = 510

x = 51000/85

x = 600

Maximum marks of each subject = 600/5 = 120

Vishal's present age = x years

Tarun's present age = 2x years

Tanvi's present age = 4x years

After 4 years.

Tarun's age = 1.5 * Vishal's age 

=> 2x + 4 = 1.5(x+4)

=> 2x - 1.5x = 2

=>0.5x = 2 => x = 2/0.5 = 4

Tanvi's present age = 16 years.

Let the original number of children be x.

3200/(x-80) - 3200/x  = 2

=> 3200((x-x+80)/(x(x-80))) = 2

=> x(x-8) = 1600 * 80

=> x(x-80) = 400(400-80)

=>x = 400

C.I = P[(1+R/100)^T - 1 ]
= P[(1+15/100)³ - 1]
= P[(23/20)³ - 1]
= P * 4167/8000
Intrest = (P * 15 * 3)/100 = 9P/20
4167P/8000 - 9P/20 = 4536
=> (4176P - 3600P)/8000 = 453.6
=> 567P = 453.6 * 8000
=> P = 453.6 * 8000/567
= Rs. 6400

Required time = LCM of 12, 8 and 15 seconds = 120 seconds means 2 minutes.