MCQs
Total Questions : 115
| Page 7 of 12 pages
Answer: Option A. -> At the liquid-gas interface
Answer: (a).At the liquid-gas interface
Answer: (a).At the liquid-gas interface
Answer: Option A. -> 0.2567
Answer: (a).0.2567
Answer: (a).0.2567
Answer: Option A. -> -2
Answer: (a).-2
Answer: (a).-2
Question 64. A sheet of Fe 1.0 mm thick is exposed to an oxidizing gas on one side and a deoxidizing gas on the other at 725°C. After reaching steady state, the Fe membrane is exposed to room temperature, and the C concentrations at each side of the membrane are 0.012 and 0.075 wt%. Calculate the diffusion coefficient (m²/sec) if the diffusion flux is 1.4×10⁻⁸kg/m²-sec.
Answer: Option A. -> 9.87*10⁻¹²
Answer: (a).9.87*10⁻¹²
Answer: (a).9.87*10⁻¹²
Answer: Option A. -> In a very dilute solution
Answer: (a).In a very dilute solution
Answer: (a).In a very dilute solution
Answer: Option A. -> The molar flux of species relative to an observer moving with the molar average velocity is proportional to the concentration gradient of the species.
Answer: (a).The molar flux of species relative to an observer moving with the molar average velocity is proportional to the concentration gradient of the species.
Answer: (a).The molar flux of species relative to an observer moving with the molar average velocity is proportional to the concentration gradient of the species.
Answer: Option B. -> 2
Answer: (b).2
Answer: (b).2
Answer: Option C. -> 0.9
Answer: (c).0.9
Answer: (c).0.9
Question 69. In industries titanium is hardened through diffusion of carbon. The concentration of carbon at 1mm into the surface of the titanium slab is 0.25kg/m³ and at 3mm the concentration is 0.68kg/m³. The rate at which the carbon is entering into its surface is 1.27*10⁻⁹kg/m².s. Calculate the value of diffusion coefficient of carbon.
Answer: Option A. -> 5.91*10⁻¹²
Answer: (a).5.91*10⁻¹²
Answer: (a).5.91*10⁻¹²