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Total Questions : 115 | Page 6 of 12 pages
Question 51. Estimate the diffusion coefficient of carbon monoxide through air in which the mole fractions of each constituents are
O₂ = 0.18
N₂ = 0.72
CO = 0.10
The gas mixture is at 300 K and 2 atmosphere total pressure. The diffusivity values are
D CO = 18.5 * 10⁻⁶ m²/s at 273 K, 1 atm
D CN = 19.2 * 10⁻⁶ m²/s at 288 K, 1 atm
The C is carbon monoxide, O is oxygen and N is nitrogen.
  1.    10.29 * 10⁻⁶ m²/s
  2.    18.5 * 10⁻⁶ m²/s
  3.    17.5 * 10⁻⁶ m²/s
  4.    13.5 * 10⁻⁶ m²/s
 Discuss Question
Answer: Option A. -> 10.29 * 10⁻⁶ m²/s
Answer: (a).10.29 * 10⁻⁶ m²/s
Question 52. What is the molecular weight of Sulphur-dioxide?
  1.    84
  2.    74
  3.    64
  4.    54
 Discuss Question
Answer: Option C. -> 64
Answer: (c).64
Question 53. For what kind of mixtures Dᴀв=Dвᴀ holds?
  1.    Ideal
  2.    Real
  3.    For both real and ideal
  4.    This relation is never true.
 Discuss Question
Answer: Option A. -> Ideal
Answer: (a).Ideal
Question 54. In the expression for molar flux Nᴀ=(Nᴀ+Nв)Cᴀ/C – DᴀвdCᴀ/dz, the terms representing bulk flow and molecular diffusion are, respectively
  1.    (Nᴀ+Nв)Cᴀ/C, DᴀвdCᴀ/dz
  2.    (Nᴀ+Nв)Cᴀ/C, DᴀвdCᴀ/dz
  3.    (Nᴀ+Nв)Cᴀ/C, (Nᴀ+Nв)Cᴀ/C
  4.    (DᴀвdCᴀ/dz, DᴀвdCᴀ/dz)
 Discuss Question
Answer: Option B. -> (Nᴀ+Nв)Cᴀ/C, DᴀвdCᴀ/dz
Answer: (b).(Nᴀ+Nв)Cᴀ/C, DᴀвdCᴀ/dz
Question 55. The dimension of diffusion coefficient is given by
  1.    MLT⁻²
  2.    L² T⁻¹
  3.    LT⁻¹
  4.    ML⁻²T
 Discuss Question
Answer: Option B. -> L² T⁻¹
Answer: (b).L² T⁻¹
Question 56. What is the density of granite in kg/m³?
  1.    2130
  2.    2230
  3.    2530
  4.    2630
 Discuss Question
Answer: Option D. -> 2630
Answer: (d).2630
Question 57. Which one is having highest density?
  1.    Leather
  2.    Paper
  3.    Balsa
  4.    Snow
 Discuss Question
Answer: Option A. -> Leather
Answer: (a).Leather
Question 58. Air at 30 degree Celsius temperature flows at 45 m/s past a wet flat plate of length 0.5 m. Estimate the value of mass transfer coefficient. Assume that the water vapor content of air initially is negligible and take the following thermos-physical properties of air.
D = 0.256 * 10⁻⁴ m²/s
µ = 1.86 * 10⁻⁵ kg/m s
cₚ = 1.005 k J/kg degree Celsius
pᵣ = 0.701
p =1.165 kg/m³
  1.    0.1076 m/s
  2.    0.2076 m/s
  3.    0.3076 m/s
  4.    0.4076 m/s
 Discuss Question
Answer: Option A. -> 0.1076 m/s
Answer: (a).0.1076 m/s
Question 59. What is the density of oak in kg/m³?
  1.    445
  2.    545
  3.    645
  4.    745
 Discuss Question
Answer: Option B. -> 545
Answer: (b).545
Question 60. Assume the following thermos-physical properties of air
D = 0.256 * 10⁻⁴ m²/s
µ = 1.86 * 10⁻⁵ kg/m s
cₚ = 1.005 k J/kg degree Celsius
pᵣ = 0.701
p =1.165 kg/m³
Find the value of Schmidt number.
  1.    0.423
  2.    0.523
  3.    0.623
  4.    0.723
 Discuss Question
Answer: Option C. -> 0.623
Answer: (c).0.623

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