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5th Grade > Mathematics

INTRODUCTION TO NUMBERS MCQs

Total Questions : 40 | Page 2 of 4 pages
Question 11. Convert 198 to Roman numerals.
  1.    CXCVIII
  2.    CLXXXXVIII
  3.    LLXCVIII
  4.    CCXVIII
 Discuss Question
Answer: Option A. -> CXCVIII
:
A
198 can be written as :
198 = 100+90+8
100 = C
90 = 100-10
90= XC
8 = VIII
198 = CXCVIII
Question 12. Ramya added 2 two digit numbers. Which of these could be the sum that she obtained?
 
  1.    18
  2.    164
  3.    199
  4.    285
 Discuss Question
Answer: Option B. -> 164
:
B
The sum of smallest 2 two-digit numbers = 10 + 10 = 20
And the sum of largest 2 digit numbers = 99 + 99 = 198
So, the sum of all the two-digit numbers will be between 20 and 198.
164 lies in between 20 and 198. So the sum that can be obtained is only 164.
18,199,285 do not lie between20 and 198, so they can not be the sum of 2 two-digit numbers.
Question 13. The Roman numeral for 2499 is ______.
  1.    MMDCLXIX
  2.    MMCCCLXIX
  3.    MMCDXCIX
  4.    MMCDXCIXX
 Discuss Question
Answer: Option C. -> MMCDXCIX
:
C
2499 = 2000 + 400 + 90 + 9
= MM + CD + XC + IX
= MMCDXCIX
( 2000 = MM, 400 = CD, 90 = XC, 9 = IX)
Question 14. The product of the place values of 6 in 438269160 divided by 1000 is
  1.    36
  2.    3600
  3.    60
  4.    600
 Discuss Question
Answer: Option B. -> 3600
:
B
Place values of 6 in438269160 are 6×10000=60000 and 6×10=60.
The product of the place values of 6 in 438269160 divided by 1000=60000×601000=36000001000=3600
Question 15. 58195 rounded off to nearest thousand is 
  1.    60000
  2.    50000
  3.    58000
  4.    59000
 Discuss Question
Answer: Option C. -> 58000
:
C
58195 Rounded Off To Nearest Thousand Is 
To round off a number to its nearest thousand we checkthe last three digits of the number i.e. the digits at the hundredsplace, tens place and ones place. In case the number formed by these is 500 or above, we round up the number to the higher value and in case the number is less than 500, we round it down to the lower value.
The given number is 58195. Our options are 58000 and 59000. The last three digits of 58195 are 195.
195 < 500.
Therefore58195 when rounding off to the nearest thousandis 58000.
Question 16. The smallest odd composite number is :
  1.    3
  2.    5
  3.    7
  4.    9
 Discuss Question
Answer: Option D. -> 9
:
D
The given options of odd numbers are: 3, 5, 7, 9.
Here3, 5 and 7 are prime numbers.
So, 9 is the smallest odd composite number.
Question 17. The successor of 101099 is _____.
  1.    101010
  2.    101100
  3.    100100
  4.    110000
 Discuss Question
Answer: Option B. -> 101100
:
B
The successor of a number is the number that comes right after it.
Thus, thesuccessor of 101099 is
101099 + 1 = 101100.
Question 18. How many basic symbols are there in Roman numerals?
 
  1.    7
  2.    8
  3.    6
  4.    4
 Discuss Question
Answer: Option A. -> 7
:
A
IVXLCDM1510501005001000
There are the 7 basic symbols in Roman numerals.
Question 19. The difference between the predecessor and the successor of 1 million is ____.
  1.    1
  2.    99999
  3.    2
  4.    100001
 Discuss Question
Answer: Option C. -> 2
:
C
1 million = 1,000,000
The successor of a number is one morethan that number and the predecessor of a number is one less than that number.
The successor of 1,000,000 = 1000000+ 1 = 1000001
The predecessor of 1,000,000 = 1000000- 1 = 999999
The difference between the successor and the predecessor of1,000,000 = 1000001 - 999999= 2.
In fact the difference between the successor and predecessor of any number will always be 2 !! Try it yourself
Question 20. How many tens make a crore?
  1.    100000
  2.    1000
  3.    10000000
  4.    1000000
 Discuss Question
Answer: Option D. -> 1000000
:
D
1 crore =1,00,00,000
Number of tens in 1 crore
=1000000010=1000000
1000000 tens make 1 crore.

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