5th Grade > Mathematics
INTRODUCTION TO NUMBERS MCQs
Total Questions : 40
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Answer: Option C. -> 7
:
C
The product of largest 3 digit number and 4 digit number 999×9999=9989001
So the product of anythree-digitnumber and a four-digit numbercannot have more than 7 digits.
:
C
The product of largest 3 digit number and 4 digit number 999×9999=9989001
So the product of anythree-digitnumber and a four-digit numbercannot have more than 7 digits.
Answer: Option B. -> LXI, XLIV, XXXVIII, XXV
:
B
For theset of Roman numerals X, XI the values are:
X = 10
XI = 11
10 < 11.
So, they are not arranged in descending order.
For theset of Roman numeralsXLV, XXII, LI, XI:
XLV = 45 and LI = 51.
45 < 51.
Therefore the set of Roman numeralsXLV, XXII, LI, XI are not arranged in descending order.
For theset of Roman numeralsXXXVIII, XLIX, LII, LXIV:
LII = 52 and LXIV = 64.
52 < 64
Therefore the set of Roman numeralsXXXVIII, XLIX, LII, LXIV are not in descending order.
For theset of Roman numerals LXI, XLIV, XXXVIII, XXV the values are:
LXI = 50 + 10 + 1 = 61
XLIV = 40 + 4 = 44
XXXVIII = 10 + 10 + 10 + 5 + 3 =38
XXV = 10 + 10 + 5 = 25
Since, 61, 44, 38, 25 are in descending order soLXI, XLIV, XXXVIII, XXV are arranged in descending order.
:
B
For theset of Roman numerals X, XI the values are:
X = 10
XI = 11
10 < 11.
So, they are not arranged in descending order.
For theset of Roman numeralsXLV, XXII, LI, XI:
XLV = 45 and LI = 51.
45 < 51.
Therefore the set of Roman numeralsXLV, XXII, LI, XI are not arranged in descending order.
For theset of Roman numeralsXXXVIII, XLIX, LII, LXIV:
LII = 52 and LXIV = 64.
52 < 64
Therefore the set of Roman numeralsXXXVIII, XLIX, LII, LXIV are not in descending order.
For theset of Roman numerals LXI, XLIV, XXXVIII, XXV the values are:
LXI = 50 + 10 + 1 = 61
XLIV = 40 + 4 = 44
XXXVIII = 10 + 10 + 10 + 5 + 3 =38
XXV = 10 + 10 + 5 = 25
Since, 61, 44, 38, 25 are in descending order soLXI, XLIV, XXXVIII, XXV are arranged in descending order.
Answer: Option B. -> 9800
:
B
The largest 2 digit number = 99
To find the successor of a number, we add 1 to it.
99 + 1 = 100
The successor of 99 = 100
To find the predecessor of a number we subtract 1 from the given number.
99 - 1 = 98
Predecessor of 99 = 98
∴ Product = 98×100=9800
:
B
The largest 2 digit number = 99
To find the successor of a number, we add 1 to it.
99 + 1 = 100
The successor of 99 = 100
To find the predecessor of a number we subtract 1 from the given number.
99 - 1 = 98
Predecessor of 99 = 98
∴ Product = 98×100=9800
Answer: Option A. -> 53
:
A
XL = 50 - 10 = 40
(∵ If a symbol of smaller value is written to the left of a symbol of greater value, then its value is subtracted from the symbol of greater value.)
XLI = 40 + 1 = 41
(∵ If a symbol of smaller value is written to the right of a symbol of greater value, then its value gets added to the symbol of greater value.)
XII = 12
∴ XLI + XII = 41 + 12 = 53
:
A
XL = 50 - 10 = 40
(∵ If a symbol of smaller value is written to the left of a symbol of greater value, then its value is subtracted from the symbol of greater value.)
XLI = 40 + 1 = 41
(∵ If a symbol of smaller value is written to the right of a symbol of greater value, then its value gets added to the symbol of greater value.)
XII = 12
∴ XLI + XII = 41 + 12 = 53
Answer: Option C. -> V, L, D
:
C
V, L, D are never repeated in the Roman numeral system.
For example,
We write 102 as 'CII'. We can't write it as 'LLII'.
:
C
V, L, D are never repeated in the Roman numeral system.
For example,
We write 102 as 'CII'. We can't write it as 'LLII'.
Answer: Option B. -> L, C
:
B
In the Roman numeral system, 'X' can be subtracted from L and C only. (L= 50) and (C= 100) For example:
XL = 50 - 10 = 40
XC = 100 -10 = 90
We can not write XD or XM.
:
B
In the Roman numeral system, 'X' can be subtracted from L and C only. (L= 50) and (C= 100) For example:
XL = 50 - 10 = 40
XC = 100 -10 = 90
We can not write XD or XM.
Answer: Option C. -> 945
:
C
CM = 900
XL = 40
V = 5
CM XL V
900 + 40 + 5 = 945
Therefore CMXLV = 945.
:
C
CM = 900
XL = 40
V = 5
CM XL V
900 + 40 + 5 = 945
Therefore CMXLV = 945.
Answer: Option D. -> 560000
:
D
To round off a number to the nearest 100 we check the last two digits of the number.
If thisnumber is 50 or more, we round up the number to the higher value (nearest higher multiple of 100).
If this number is less than 50, we round down the number to the lower value.( nearest lower multiple of 100)
For 677, 70 > 50. So it is rounded off to 700.
For 833, 30 < 50. So it is rounded off to 800.
So, the given numbers are rounded to 700 and 800.
∴ Product = 700×800
= 560000
:
D
To round off a number to the nearest 100 we check the last two digits of the number.
If thisnumber is 50 or more, we round up the number to the higher value (nearest higher multiple of 100).
If this number is less than 50, we round down the number to the lower value.( nearest lower multiple of 100)
For 677, 70 > 50. So it is rounded off to 700.
For 833, 30 < 50. So it is rounded off to 800.
So, the given numbers are rounded to 700 and 800.
∴ Product = 700×800
= 560000
Answer: Option A. -> Ones place
:
A
The place value and the face value of a digit in a numberare always equal at the ones/units place.
For example in 987,
H T O
9 8 7
The face value of 8 = 8
The place value of 8 = 80
The face vlaue of 9 = 9
The place value of 9 = 900
But, The face vlaue of 7 = 7
The place value of 7 = 7
:
A
The place value and the face value of a digit in a numberare always equal at the ones/units place.
For example in 987,
H T O
9 8 7
The face value of 8 = 8
The place value of 8 = 80
The face vlaue of 9 = 9
The place value of 9 = 900
But, The face vlaue of 7 = 7
The place value of 7 = 7
Answer: Option B. -> 1011467
:
B
To find the smallest number wefirst arrange the given digits in ascending order.
0 < 1 < 4 < 6 < 7
Since we cannotwrite a number starting with '0' we have to write it in 2nd position.
So our required order will be 1, 0, 4, 6, 7.
We have to make the smallest 7 digit number using the given digits, so we need 2 more digits.
To make the smallest 7 digit number we will use 1, which is the 2nd smallest digit (∵ we have to make the number without repeating 0).
So the smallest 7 digit number using the digits 4, 0, 1, 7, 6 without repeating 0 is1011467.
:
B
To find the smallest number wefirst arrange the given digits in ascending order.
0 < 1 < 4 < 6 < 7
Since we cannotwrite a number starting with '0' we have to write it in 2nd position.
So our required order will be 1, 0, 4, 6, 7.
We have to make the smallest 7 digit number using the given digits, so we need 2 more digits.
To make the smallest 7 digit number we will use 1, which is the 2nd smallest digit (∵ we have to make the number without repeating 0).
So the smallest 7 digit number using the digits 4, 0, 1, 7, 6 without repeating 0 is1011467.