Answer: Option A. -> True
:
A
According to Newton's third law, when a body $A$ exertsa force on another body $B$, $B$ also exerts an equal and opposite force on $A$. Hence, while kicking a ball, the footballer's leg will experience an equal amountof force but in opposite direction to that of theforce he exerted on the ball.

Answer: Option D. -> 4 N
:
D
Initial velocity of the stone = $20m{s}^{-1}$.
Final velocity of the stone, $v=0$(finally the stone comes to rest).
Distance covered by the stone = 50 m.
According to third equation of motion:
$v^2=u^2+2as$
0 × 0 = 20 × 20 + 2 × a × 50
$\Rightarrow$$a=-4m{s}^{-2}$.
The negative sign indicates that acceleration is in the opposite direction to the motion ofthe stone.
Mass of the stone, $m=1kg$.
From the newton's second law of motion:
Force = mass × acceleration. Therefore,
$F=1\times -4=-4N$.
Hence, the force of friction between the stone and the ice is 4N. The negative sign indicates that friction oppposes the relative motion.

Answer: Option A. -> True
:
A
The weight of the object exerts a force on the table. The table in return exerts a reactionforce which is equal to the magnitude of the weight and opposite in direction(Newton's third law).Thus, the net force on the object is zero as two equal forces in opposite directions are acting on it and hence the object remains at rest.

Answer: Option B. -> mass of body remains constant
:
B
Newton's second lawstates that the rate of change of momentumof an object is directly proportional to the net force acting on it, provided that the mass of the body is kept constant. It gives the mathematical expression of force.

Answer: Option C. ->  4500 N
:
C
Here, mass m = $1500kg$
Initial velocity, u = 0, final velocity, v = $30m{s}^{-1}$, time taken, t = $10s$.
Now, putting these values in the first equation of motion,$v=u+at$, we get
$30=0+a\times t$,
$\Rightarrow$ $10a=30$
$\Rightarrow$ $a=3m{s}^{-2}$
Now, putting $m=1500kg$and a =$3m{s}^{-2}$ in equation, $F=m\times a$, we get
$F=1500\times 3$ = $4500N$.
Thus, the force required is$4500N$.

Answer: Option D. ->  10 kg
:
D
Given, force, $F=30N$and acceleration, $a=3{ms}^{-2}$.
Let m be the mass of the body.
We know, $F=ma$ (Newtons's second law of motion)
$\therefore$ $m=\frac{F}{a}=\frac{30}{3}=10kg$
Therefore, mass of the body is $10kg$.

Answer: Option A. ->  4,000 N 
:
A
For calculating force, we need to calculate deceleration first. From thethird equation of motion,
$v^2-u^2=2aS$ where, v- final velocity, u- initial velocity, a- acceleration and S- distance travelled.
Given, u=$20m{s}^{-1}$, S$=50m$, mass $m=1000kg$ and v$=0$.
Therefore, $0-{20}^2=2\times a\times 50$
$\Rightarrow a=-4m{s}^{-2}$
Let the force acting on the car be $F$.
From Newton's second law,
$F=ma$
$\Rightarrow F=1000\times (-4)=-4000\text{N}$
Hence, the net force is$-4,000N$. The negative sign indicates that the force is acting opposite to the direction of initial velocity and causes deceleration. This net force is actually the frictional force acting between the ground and the tyre of the car.

Answer: Option A. -> Force
:
A
From, Newton's second law of motion, we know , $F=m\times a$ where $F$ is the force applied, $m$ is the mass and $a$ is the acceleration. The SI unit of mass is $kg$ and acceleration is $m{s}^{-2}$. So, the SI unit of force is $kgm{s}^{-2}$, also known as Newton(N).

Answer: Option A. -> True
:
A
Inertia is the natural tendency of an object to resist a change in its state of motion or of rest. Quantitatively, the inertia of an object is measured by its mass. More the mass more will be its inertia. As object A is heavier than object B, it has more inertia.

Answer: Option B. -> move forward
:
B
When the tanker is in motion, the water inside will also be in motion. When the tanker comes to an abrupt stop, the water's inertia of motion resists this sudden change in motion. As a result, the water will move forward, before eventually coming to rest.