Exams > Cat > Di And Lr
DI AND LR CLUBBED MCQs
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Answer: Option D. -> 3
:
D
Red will win 3 matches in the first round
:
D
Red will win 3 matches in the first round
Answer: Option A. -> 2
:
A
There can be two cases for the scheduled day of exams, since on every unique day of the week, there is atleast one exam:
Case I:MonTueThurSatMonWedFri
This is not possible as exams end on Saturday.
CaseIIMonWedFriSatTueThursSatPhyChemCompBioMathEcoEngOrChemCompPhy/MathBioEngEcoMath/PhyOrEngEconMathBioChemCompPhyOrPhy/MathEcoEngBioMath/PhyChemComp
:
A
There can be two cases for the scheduled day of exams, since on every unique day of the week, there is atleast one exam:
Case I:MonTueThurSatMonWedFri
This is not possible as exams end on Saturday.
CaseIIMonWedFriSatTueThursSatPhyChemCompBioMathEcoEngOrChemCompPhy/MathBioEngEcoMath/PhyOrEngEconMathBioChemCompPhyOrPhy/MathEcoEngBioMath/PhyChemComp
Answer: Option D. -> (E)
:
D
We get two values even on combining both cases.
Case 1: x = -3, y = 4, z = 5 x + z = 2 < 3 x + y + z = 6
Case 2: x = -3, y = -2, z = -1 x + z = -4 < 3 x + y + z = -6
Hence both statements together are also insufficient
:
D
We get two values even on combining both cases.
Case 1: x = -3, y = 4, z = 5 x + z = 2 < 3 x + y + z = 6
Case 2: x = -3, y = -2, z = -1 x + z = -4 < 3 x + y + z = -6
Hence both statements together are also insufficient
Answer: Option A. -> 1:4
:
A
Let the numbers of cars sold by different manufactures is as shown below.
P - a
Q - b
R - c
S - d
T - e
PQRSTB0.24a0.16b0.32c0.24d0.28eB+0.16a0.24b0.10c0.16d0.08eC0.18a0.24b0.15c0.32d0.12eD0.36a0.20b0.35c0.24d0.48eE0.06a0.16b0.08c0.04d0.04e
Let the numbers of cars sold by different segments is as shown below.
B - v
B+ - w
C - x
D - y
E - z
BB+CDEP0.15v0.20w0.15x0.18y0.15zQ0.05v0.15w0.10x0.05y0.20zR0.40v0.25w0.25x0.35y0.40zS0.225v0.30w0.40x0.18y0.15zT0.175v0.10w0.10x0.24y0.10z
From the above two tables, the ratio of number of cars sold by S in the E segment to that of P in the B segment is 1:4.
:
A
Let the numbers of cars sold by different manufactures is as shown below.
P - a
Q - b
R - c
S - d
T - e
PQRSTB0.24a0.16b0.32c0.24d0.28eB+0.16a0.24b0.10c0.16d0.08eC0.18a0.24b0.15c0.32d0.12eD0.36a0.20b0.35c0.24d0.48eE0.06a0.16b0.08c0.04d0.04e
Let the numbers of cars sold by different segments is as shown below.
B - v
B+ - w
C - x
D - y
E - z
BB+CDEP0.15v0.20w0.15x0.18y0.15zQ0.05v0.15w0.10x0.05y0.20zR0.40v0.25w0.25x0.35y0.40zS0.225v0.30w0.40x0.18y0.15zT0.175v0.10w0.10x0.24y0.10z
From the above two tables, the ratio of number of cars sold by S in the E segment to that of P in the B segment is 1:4.
Answer: Option B. -> 6
:
B
There can be two cases for the scheduled day of exams, since on every unique day of the week, there is atleast one exam:
Case I:MonTueThurSatMonWedFri
This is not possible as exams end on Saturday.
CaseIIMonWedFriSatTueThursSatPhyChemCompBioMathEcoEngOrChemCompPhy/MathBioEngEcoMath/PhyOrEngEconMathBioChemCompPhyOrPhy/MathEcoEngBioMath/PhyChemComp
:
B
There can be two cases for the scheduled day of exams, since on every unique day of the week, there is atleast one exam:
Case I:MonTueThurSatMonWedFri
This is not possible as exams end on Saturday.
CaseIIMonWedFriSatTueThursSatPhyChemCompBioMathEcoEngOrChemCompPhy/MathBioEngEcoMath/PhyOrEngEconMathBioChemCompPhyOrPhy/MathEcoEngBioMath/PhyChemComp
Answer: Option B. -> Red and Blue
:
B
Red and Blue
:
B
Red and Blue
Answer: Option D. -> 4
:
D
The goal difference of all teams must add up to 0.Hence GD of Chelsea = -2
If 6 goals have been scored against it, it must have scored 4 goals.
:
D
The goal difference of all teams must add up to 0.Hence GD of Chelsea = -2
If 6 goals have been scored against it, it must have scored 4 goals.
Question 28. The high school math department needs to appoint a new chairperson, which will be based on seniority. Ms. "A” has less seniority than Mr. "B”, but more than Ms. "C”. Mr. "D” has more seniority than Ms. "A”, but less than Mr. "B”. Mr. "B” doesn't want the job. Who will be the new math department chairperson?
Answer: Option A. -> Mr. "D”
:
A
Mr. "B” has the most seniority, but he does not want the job. Next in line is Mr. "D”, who has more seniority than Ms. "A” or Ms. "C”.
:
A
Mr. "B” has the most seniority, but he does not want the job. Next in line is Mr. "D”, who has more seniority than Ms. "A” or Ms. "C”.
Question 29. Watchman A has worked more night shifts in a row than Watchman B, who has worked five. Watchman C has worked fifteen night shifts in a row, more than Watchman A and Watchman B combined. Watchman D has worked eight night shifts in a row, less than Watchman A. How many night shifts in a row has Watchman A worked?
Answer: Option B. -> nine
:
B
Watchman A has worked more shifts in a row than Watchman D; therefore, Watchman A has worked more than eight shifts. The number of Watchman A's shifts plus the number of Watchman B's shifts (five) cannot equal fifteen or more, the number of Watchman C's shifts. Therefore, Watchman A has worked nine shifts in a row (5 + 9 = 14). Therefore, option (b) is the correct answer choice.
:
B
Watchman A has worked more shifts in a row than Watchman D; therefore, Watchman A has worked more than eight shifts. The number of Watchman A's shifts plus the number of Watchman B's shifts (five) cannot equal fifteen or more, the number of Watchman C's shifts. Therefore, Watchman A has worked nine shifts in a row (5 + 9 = 14). Therefore, option (b) is the correct answer choice.
:
Ans: 2011
The number of fresh recruits would grow as:
Year20072008200920102011Jacobsons(′00)365401.5441.65485.82534.4Richardsons(′00)259310.8372.96447.55537.06Total624712.3814.61933.371071.46