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8th Grade > Mathematics

CUBES AND CUBE ROOTS MCQs

Total Questions : 57 | Page 3 of 6 pages
Question 21. Amrit's teacher told him "Go to shop A and buy 3 chocolates. Then go to shop B and buy thrice the number of chocolates you have and eat 3 chocolates. Then go to shop C and again buy thrice the number of chocolates you have." What will be the number of chocolates left with Amrit at the end?
  1.    27
  2.    36
  3.    48
  4.    45
 Discuss Question
Answer: Option B. -> 36
:
B
Number of chocolates Amrit has after going to shop A = 3
Number of chocolates Amrit has after going to shop B = 3 x 3 + 3 = 12
Number of chocolates Amrit has after shop B and eating 3 = 12 - 3 = 9
Number of chocolates Amrit has after going to shop C = 3 x 9 + 9 = 36
Hence, the number of chocolates Amrit has at the end is 36.
Question 22. Find the number whose square is the sum of the cube of the first 5 natural numbers.
  1.    10
  2.    12
  3.    13
  4.    15
 Discuss Question
Answer: Option D. -> 15
:
D
The sum of first 5 natural numbers can be expressed as (n(n+1)2)2 where n = 5, which gives us
((5×6)2)2 =(302)2 = 152
Thus the cubes of first 5 natural numbers can be expressed as the square of 15.
Question 23. What is the value of  38138 ?
  1.    2
  2.    2.5
  3.    0.5
  4.    1
 Discuss Question
Answer: Option B. -> 2.5
:
B
8= 2 x 2 x 2
Cube root of 8 = 2
So 2+ 12= 2.5
Question 24. How many perfect cubes are there between 0 and 100?
  1.    2
  2.    3
  3.    4
  4.    5
 Discuss Question
Answer: Option C. -> 4
:
C
Cube of 1 = 1
Cube of 2 = 8
Cube of 3 = 27
Cube of 4 = 64
So total 4 numbers have their cubes that lie between 0 and 100
Question 25. The cube of 0 is 
___
 Discuss Question

:
Cube of 0 is 0(anything multiplied to 0 is 0)
Question 26. Find the cube root of 216 × 729.
  1.    54
  2.    9
  3.    6
  4.    51
 Discuss Question
Answer: Option A. -> 54
:
A
216 is the cube of 6 as 216 can be expressed as (6×6×6)
729 is the cube of 9 as 729 can be expressedas (9×9×9)
36×6×6×39×9×9
= 6×9
So the cube root of the product will be 6 × 9 = 54.
Question 27. How many cubes of side length 3 can be fit in a cuboid of dimension 3×6×9?
  1.    2
  2.    6
  3.    9
  4.    10
 Discuss Question
Answer: Option B. -> 6
:
B
Volume of cuboid = 3×6×9 =162 cubic units
Volume of cube = 3×3×3= 27 cubic units
Number of cubes that can be fit in the cuboid is 16227= 6
Question 28.


Amrit's teacher told him "Go to shop A and buy 3 chocolates. Then go to shop B and buy thrice the number of chocolates you have and eat 3 chocolates. Then go to shop C and again buy thrice the number of chocolates you have." What will be the number of chocolates left with Amrit at the end?


  1.     27
  2.     36
  3.     48
  4.     45
 Discuss Question
Answer: Option B. -> 36
:
B

Number of chocolates Amrit has after going to shop A = 3
Number of chocolates Amrit has after going to shop B = 3 x 3 + 3 = 12
Number of chocolates Amrit has after shop B and eating 3 = 12 - 3 = 9
Number of chocolates Amrit has after going to shop C = 3 x 9 + 9 = 36
Hence, the number of chocolates Amrit has at the end is 36.


Question 29.


The digit in the units place in the cube of 298 is 


  1.     2
  2.     3
  3.     8
  4.     4
 Discuss Question
Answer: Option A. -> 2
:
A

The digit in the units place in 298 is 8.
cube of 8 is 512, which ends in 2.
Hence, the digit in the units place in the cube of 298 is 2 


 


Question 30.


Find the cube root of 216 × 729.


  1.     54
  2.     9
  3.     6
  4.     51
 Discuss Question
Answer: Option A. -> 54
:
A

216 is the cube of 6 as 216 can be expressed as (6×6×6)


729 is the cube of 9 as 729 can be expressed as (9×9×9)


36×6×6×39×9×9
= 6×9
So the cube root of the product will be 6 × 9 = 54.


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