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8th Grade > Mathematics

CUBES AND CUBE ROOTS MCQs

Total Questions : 57 | Page 2 of 6 pages
Question 11. The volume of a closed cubical tank is 1331 cubic metres. Find the cost of painting its complete surface area from outside at the rate of  10 per square meter.
  1.    7260
  2.    7240
  3.    7000
  4.    7280
 Discuss Question
Answer: Option A. -> 7260
:
A
Let the side of the given cubical tank be 'a' metres .
Volume of the given cube is a×a×a
By prime factorization, we get cube root of 1331 as 11
Surface area of each side of a cube is a×a
Total surface area of the cube is 6×a×a
Cost incurred is then 10×6×11×11=7260
Question 12. The difference of cubes of two consecutive numbers is always divisible by 3.
  1.    True
  2.    False
  3.    441
  4.    788
 Discuss Question
Answer: Option B. -> False
:
B
Take two numbers, for example, 2 and 1 and check.
The difference of cubes of 2 and 1 is 7, which is not divisible by 3.
Question 13. If the value of (a3b3a3+b3)  when a = 7 and b = 2 is 335p, then p is 321.
  1.    True
  2.    False
  3.    441
  4.    788
 Discuss Question
Answer: Option B. -> False
:
B
a3- b3= (ab)( a2+ab+ b2)
a3+ b3=(a+b)( a2-ab+ b2)
Puting the values of a and b,weget the value of p as 351.
Alternatively, we can observe that since a and b are positive, so denominator has to be greater than numerator. Thus,
a3+ b3will be greater thana3-b3
Question 14. The units digit in the expansion of 163 is
___
 
 Discuss Question

:
The units digit of the cube of any number with 6 in its unit's place is always 6. Alternatively, we can see that 6 when multiplied with itself three times yields 216, whose last digit is 6.
Question 15. What is the units digit of the cube of the number whose unit digit is 7?
  1.    3
  2.    5
  3.    4
  4.    2
 Discuss Question
Answer: Option A. -> 3
:
A
The units digit of the cube of 7 i.e.343 is 3.
Thus, the units digit of the cube of the number whose unit digit is 7 will be 3.
Question 16. With what number should 1715 be divided to get a perfect cube?
  1.    1
  2.    7
  3.    5
  4.    Already a perfect cube
 Discuss Question
Answer: Option C. -> 5
:
C
For a numberto be a perfect cube, its prime factors should be expressed as triplets
By prime factorization,we get 1715 = 7×7×7×5
We have three 7’s but only one 5 so we need to divide the number by 5.
Question 17. 100 is the smallest square number that is the sum of cubes of 4 consecutive natural numbers.
  1.    True
  2.    False
  3.    5
  4.    Already a perfect cube
 Discuss Question
Answer: Option A. -> True
:
A
100 = 102
= 13+ 23+ 33+ 43
= 1+8+27+64
Question 18. Anshul and Balendu have 50 cubes of side 1 cm. They decided to make a larger cube by joining these smaller cubes. The number of larger cubes (all of different sizes) they can make is 
___
 Discuss Question

:
Since the side of the smaller cube is 1 cm, its volume will be 1 cubic cm.
We know that the volume of cubes of sides 1,2,3,4,... are 1,8,27,64...cubic cm.
But Anshul and Balendu have only 50 small cubes, so they can make cubes of 3 sizes with the help of 1,8 and 27 smaller cubes.
It should be noted that (50-1-8-27) = 14 smaller cubes will be left unused.
Question 19. What should be multiplied to 43200 to make it a perfect cube?
  1.    2
  2.    3
  3.    5
  4.    Already a perfect cube
 Discuss Question
Answer: Option C. -> 5
:
C
For a number to be a perfect cube, its prime factors should be in the form of triplets
By prime factorization, 43200 = 26× 33× 52
Only two 5’s are there so we need one more 5 to make a triplet.
So if 43200 is multiplied by 5, we get a perfect cube.
Question 20. Which of these is not a perfect cube?
  1.    343
  2.    1331
  3.    512
  4.    81
 Discuss Question
Answer: Option D. -> 81
:
D
By prime factorization, we have
343=7×7×71331=11×11×11512=8×8×881=3×3×3×3
For a number to be a perfect cube ,each of its factors must be repeated thrice.
343, 1331 and 512 are the perfect cubes of 7, 11 and 8 respectively, whereas 81 is not, as 3 is repeating 4 times which is not a triplet.
81 is not a perfect cube.

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