Reasoning Aptitude
CODING AND DECODING MCQs
Coding-Decoding
Total Questions : 673
| Page 64 of 68 pages
Question 631.
Directions:
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
640598
Directions:
In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
640598
Answer: Option A. -> TDJRMN
Answer: (a)
6 is coded as T, 4 as D, 0 as J, 5 as R, 9 as M, 8 as N.
Answer: (a)
6 is coded as T, 4 as D, 0 as J, 5 as R, 9 as M, 8 as N.
Question 632.
Directions:
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
893561
Directions:
In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
893561
Answer: Option D. -> YMERTY
Answer: (d)
Since the given number-group begins with an even number and ends with an odd number,
so both the first and last digits
i.e. 8 and 1 shall be coded as Y.
9 is coded as M, 3 as E, 5 as R, 6 as T.
So, the code for 893561 is YMERTY.
Answer: (d)
Since the given number-group begins with an even number and ends with an odd number,
so both the first and last digits
i.e. 8 and 1 shall be coded as Y.
9 is coded as M, 3 as E, 5 as R, 6 as T.
So, the code for 893561 is YMERTY.
Question 633.
Directions:
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
328469
Directions:
In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
328469
Answer: Option E. -> None of these
Answer: (e)
3 is coded as E, 2 as B, 8 as N, 4 as D, 6 as T, 9 as M.
Answer: (e)
3 is coded as E, 2 as B, 8 as N, 4 as D, 6 as T, 9 as M.
Question 634.
Directions:
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
743506
Directions:
In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
743506
Answer: Option C. -> XDERJX
Answer: (c)
Since the first digit is an odd number and the last digit is an even number,
so both 7 and 6 shall be coded as X.
4 is coded as D, 3 as E, 5 as R, 0 as J.
So, the code for 743506 is XDERJX.
Answer: (c)
Since the first digit is an odd number and the last digit is an even number,
so both 7 and 6 shall be coded as X.
4 is coded as D, 3 as E, 5 as R, 0 as J.
So, the code for 743506 is XDERJX.
Question 635.
Directions:
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
631420
Directions:
In each of the questions given below, a group of digits followed by four combinations of letter codes labelled (a), (b), (c) and (d) are given. You have to find out which of the combinations is correct coded form of the group of digits as per the following codes and conditions. If none of these four combinations is correct, give your answer as (e). i.e., 'None of these' as the answer.
Digit
9
3
2
8
1
5
7
6
4
0
Letter Code
M
E
B
N
K
R
H
T
D
J
Conditions:
If the first digit is an odd number and the last digit is an even number, both are to be coded as 'X'.
If the first digit is an even number and the last digit is an odd number, both are to be coded as 'Y'.
If either the first or the last digit is 0, then 0 is to be coded as 'W'.
[Asstt, Manager Exam, 2005]
631420
Answer: Option B. -> TEKDBW
Answer: (b)
Since the last digit is 0, so 0 shall be coded as W. 6 is coded as T, 3 as E, 1 as K, 4 as D, 2 as B.
So, the code for 631420 is TEKDBW.
Answer: (b)
Since the last digit is 0, so 0 shall be coded as W. 6 is coded as T, 3 as E, 1 as K, 4 as D, 2 as B.
So, the code for 631420 is TEKDBW.
Answer: Option A. -> 3 % * 4 1
Answer: (a)
As, B → 5 A → $ S → 3 K → % E → # T → 1 and T → 1 R → 4 I → * E → # D → 2
Similarly, S → 3 K → % I → * R → 4 T → 1
Therefore, SKIRT ⇒ 3%*41
Answer: (a)
As, B → 5 A → $ S → 3 K → % E → # T → 1 and T → 1 R → 4 I → * E → # D → 2
Similarly, S → 3 K → % I → * R → 4 T → 1
Therefore, SKIRT ⇒ 3%*41
Answer: Option C. -> 3 # % 5
Answer: (c)
As, S → 5 A → @ F → 3 E → # R → 2 and R → 2 I → © D → % E → #
Similarly, F → 3 E → # D → % S → 5
Therefore, FEDS → 3 # % 5
Answer: (c)
As, S → 5 A → @ F → 3 E → # R → 2 and R → 2 I → © D → % E → #
Similarly, F → 3 E → # D → % S → 5
Therefore, FEDS → 3 # % 5
Answer: Option D. -> None of these
Answer: (d)As, R → % A → # I → £ D → $ and R → % I → £ P → @ E → ©
Similarly, D → $ E → © A → # R %
Therefore, DEAR ⇒ $ © # %
Answer: (d)As, R → % A → # I → £ D → $ and R → % I → £ P → @ E → ©
Similarly, D → $ E → © A → # R %
Therefore, DEAR ⇒ $ © # %
Answer: Option B. -> 3 * $ 5
Answer: (b)
AS, S → 5 T → $ A → * R → 2 and T → $ O → 3 R → 2 E → @
Similarly, o → 3 A → * T → $ S → 5
Therefore, OATS ⇒ 3 * $ 5
Answer: (b)
AS, S → 5 T → $ A → * R → 2 and T → $ O → 3 R → 2 E → @
Similarly, o → 3 A → * T → $ S → 5
Therefore, OATS ⇒ 3 * $ 5
Answer: Option B. -> 8 @ 7 $ % 6
Answer: (b)
As, R → 8 A → $ I → % N → 6 and M → 7 O → # R → 8 E → @
Similarly, R → 8 E → @ M → 7 A → $ I → % N → 6
Therefore, REMAIN ⇒ 8 @ 7 $ % 6
Answer: (b)
As, R → 8 A → $ I → % N → 6 and M → 7 O → # R → 8 E → @
Similarly, R → 8 E → @ M → 7 A → $ I → % N → 6
Therefore, REMAIN ⇒ 8 @ 7 $ % 6
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