Quantitative Aptitude
CLOCK MCQs
Total Questions : 223
| Page 23 of 23 pages
Answer: Option B. -> 75°
$$\eqalign{
& {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,\frac{{17}}{2}\,{\text{hrs}} \cr
& {\text{ = }}\,{\left( {\frac{{360}}{{12}} \times \frac{{17}}{2}} \right)^ \circ } \cr
& = 255^ \circ \cr
& {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{min}}{\text{.}}\,{\text{hand}}\,{\text{in}}\,{\text{30}}\,{\text{min}} \cr
& = {\left( {\frac{{360}}{{60}} \times 30} \right)^ \circ } \cr
& = 180^ \circ \cr
& \therefore {\text{Required}}\,{\text{angle}} \cr
& = {\left( {255 - 180} \right)^ \circ } = {75^ \circ } \cr} $$
$$\eqalign{
& {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,\frac{{17}}{2}\,{\text{hrs}} \cr
& {\text{ = }}\,{\left( {\frac{{360}}{{12}} \times \frac{{17}}{2}} \right)^ \circ } \cr
& = 255^ \circ \cr
& {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{min}}{\text{.}}\,{\text{hand}}\,{\text{in}}\,{\text{30}}\,{\text{min}} \cr
& = {\left( {\frac{{360}}{{60}} \times 30} \right)^ \circ } \cr
& = 180^ \circ \cr
& \therefore {\text{Required}}\,{\text{angle}} \cr
& = {\left( {255 - 180} \right)^ \circ } = {75^ \circ } \cr} $$
Answer: Option C. -> $$49\frac{1}{{11}}$$ min. past 9
To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.
55 min. spaces gained in 60 min.
45 min. spaces are gained in
$$\left( {\frac{{60}}{{55}} \times 45} \right){\text{min}}{\text{.}}{\kern 1pt} \,{\text{or}}{\kern 1pt} \,49\frac{1}{{11}}{\kern 1pt} {\text{min}}.$$
∴ The hands are together at $$49\frac{1}{{11}}$$ min. past 9
To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.
55 min. spaces gained in 60 min.
45 min. spaces are gained in
$$\left( {\frac{{60}}{{55}} \times 45} \right){\text{min}}{\text{.}}{\kern 1pt} \,{\text{or}}{\kern 1pt} \,49\frac{1}{{11}}{\kern 1pt} {\text{min}}.$$
∴ The hands are together at $$49\frac{1}{{11}}$$ min. past 9
Answer: Option C. -> 156
Total number of strikings
$$\eqalign{
& = 2\left( {1 + 2 + 3 + ..... + 12} \right) \cr
& = 2 \times \frac{{12 \times 13}}{2} \cr
& = 156 \cr} $$
Total number of strikings
$$\eqalign{
& = 2\left( {1 + 2 + 3 + ..... + 12} \right) \cr
& = 2 \times \frac{{12 \times 13}}{2} \cr
& = 156 \cr} $$