Answer: Option C. -> 1996
Answer: (c)
The year 1990 has 365 days. i.e. 1 odd day,
the year 1991 has 365 days, i.e. 1 odd day,
the year 1992 has 366 days i.e. 2 odd days.
The likewise year 1993, 1994, 1995 have 1 odd day each.
The sum of odd days, so calculated from years 1990 - 95
= (1 + 1 + 2 + 1 + 1 + 1) = 7 days = 0 odd day
Hence, the year 1996 will have the same calendar as that of the year 1990.

Answer: Option A. -> Day after tomorrow
Answer: (a)
Day before yesterday = Thursday
Therefore, Today = Thursday + 2 = Saturday
Therefore, Monday = Saturday + 2 = Day after tomorrow

Answer: Option A. -> Tuesday
Answer: (a)
Total number of days from January 1 to March 1
= 30 + 29 + 1 = 60 days
(February in leap years = 29 days)
60 ÷ 7 = 8 weeks and 4 odd days
So, the fourth day from Friday = Tuesday

Answer: Option D. -> Friday
Answer: (d)
Three days after Saturday is Tuesday and Tuesday is the day before a day before yesterday
So, yesterday is Thursday and today is Friday.

Answer: Option D. ->  Wednesday
 Answer: (d)
Day before yesterday = Saturday
Today = Saturday + 2 = Monday
Therefore, Tomorrow = Monday + 1 = Tuesday
Therefore, Day after tomorrow = Tuesday + 1 = Wednesday

Answer: Option C. -> Monday
Answer: (c)
Three days after today = Tuesday
Today = Tuesday - 3 = Saturday
Yesterday = Saturday - 1 = Friday
Therefore, 4 days before yesterday = Friday - 4 = Monday

Answer: Option C. -> Tomorrow
Answer: (c)
A day before yesterday = Thursday
Yesterday = Thursday + 1 = Friday
Today = Friday + 1 = Saturday
Therefore, Sunday = Saturday + 1 = Tomorrow

Answer: Option B. -> Friday
Answer: (b)
15 August 1947 means,
1946 complete years + first 7 months up to July 1947 + 15 days of August 1947
1600 years have 0 odd days.
300 years have 1 odd day
46 years have 11 leap years and
35 ordinary years = (11 × 2) + (35 × 1)
= 22 + 35 = 57 odd days
= 8 × 7 + 1 odd days = 8 weeks + 1 odd day
Up to 1946 there are 1 + 1 = 2 odd days
January 1947 = 3 odd days
February 1947 = 0 odd days (1947 is a normal year)
March 1947 = 3 odd days
April 1947 = 2 odd days
May 1947 = 3 odd days
June 1947 = 2 odd days
July 1947 = 3 odd days
Up to 15 August = 15 odd days
Total number od odd days up to 15 August 1947
= 2 + 3 + 0 + 3 + 2 + 3 + 2 + 3 + 15
= 33 odd days.
Hence, 15th August 1947 was Friday.

Answer: Option C. -> Sunday
Answer: (c)

Answer: Option C. -> Wednesday
Answer: (c)
2 days before yesterday = Friday
∴ Yesterday = Friday + 2 = Sunday
∴ Today = Sunday + 1 = Monday
∴  Day after tomorrow = Monday + 2 = Wednesday