Answer: Option A. -> Thursday
Answer: (a)
A day after tomorrow = Tuesday
∴ Two days after the day after tomorrow = Tuesday + 2
= Thursday

Answer: Option A. -> Thursday
Answer: (a)
Two days after tomorrow = Thursday
Tomorrow = Thursday - 2 = Tuesday
Today = Tuesday - 1 = Monday
Yesterday = Monday - 1 = Sunday
∴ 3 days before yesterday = Sunday - 3 = Thursday

Answer: Option D. -> A day after tomorrow
Answer: (d)
A day before yesterday = Wednesday
Yesterday = Wednesday + 1 = Thursday
Today = Thursday + 1 = Friday
∴ Sunday = Friday + 2 = Day after tomorrow.

Answer: Option B. -> Wednesday
Answer: (b)
Day after tomorrow = Sunday
Tomorrow = Sunday - 1 = Saturday
Today = Saturday - 1 = Friday
Yesterday = Friday - 1 = Thursday
∴ Day before yesterday = Thursday -1=Wednesday

Answer: Option C. -> Thursday
Answer: (c)
4th Saturday = 22nd day
3rd Saturday = 22 - 7 = 15th day
∴ 13th day - Saturday - 2 = Thursday

Answer: Option C. -> Tuesday
Answer: (c)
Here, 27th March 1995 was Monday.
Now, for calculating the total number of odd days. first, we calculate the total number of days till 1 November 1994.
∴  Number of days in March, 1995 = 27
Number of days in February 1995 = 28
Number of days in January 1995 = 31
Number of days in December 1994 = 31
Number of days in November 1994 = 29
Total number of days = 146
∴ Number of odd days = $146/7$ = 20$6/7$
So, 6 odd days
∴ On November 1, 1994 = Monday - 6
= Tuesday

Answer: Option D. -> Sunday
Answer: (d)
Since Total days from 15th August, 2011 to 17 September, 2011 = 33
33 ÷ 7 => 7)33(4 = remainder 5 odd days
∴ Required day = Tuesday + 5 odd days
= Sunday

Answer: Option B. -> Tuesday
Answer: (b)
Tomorrow = Friday
3 days after tomorrow = 15th June = Friday + 3 odd days = Monday
Days from 15th to 30th June = 15
15 ÷ 7 = 7)15(2 =>remainder 1 odd day
30th June = Monday + 1 odd day = Tuesday

Answer: Option B. -> Monday
Answer: (b)
1st April 1901 means 1900 complete years + first 3 months of 1901 + 1 day of April
Number of odd days in 1600 yrs = 0
Number of odd days in 300 yrs = 1
Number of odd days in 1901 yrs
January
3
February
0
March
3
April
1
= 3 + 0 + 3 + 1 = 7
⇒ 0 odd days
Total number of odd days till 1st April 1901 = 0 + 1 + 0 = 1
So, the required day was Monday.

Answer: Option A. -> Monday
Answer: (a)
15th August 1949 means,
1948 complete year + First 7 months of the year 1949 + 15 days of August
Number of odd days in 1600 yrs = 0
Number of odd days in 300 yrs = 1
Number of odd days in 48 yr (36 non - leap years + 12 leap years)
= 36 × 1 + 12 × 2
= 60 = 7 × 8 + 4 = 4
odd days From 1st January 1949 to 15th August 1949
Number of odd days in 1949,
January
3
February
0
March
3
April
2
May
3
June
2
July
3
August
(15 ÷ 7) = 1
Total number of odd days in 1949 = 3 + 0 + 3 + 2 + 3 + 2 + 3 + 1 = 17
= 7 × 2 + 3 = 3 odd day
Total odd days = 1 + 4 + 3 = 8
= 1 odd days
Since, 1 is the code for Monday.
Therefore, the required day was Monday.