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MCQs

Total Questions : 115 | Page 2 of 12 pages
Question 11. Determine the correctness or otherwise of the following Assertion (a) and Reason (r). Assertion: In direct somatic embryogenesis, embryos are developed without going through callus
formation. Reason: This is possible due to the presence of pre-embryonically determined cells.
  1.    Both (a) and (r) are true but (r) is not the correct reason for (a)
  2.    (a) is false but (r) is true
  3.    (a) is true but (r) is false
  4.    Both (a) and (r) are true and (r) is the correct reason for (a)
 Discuss Question
Answer: Option D. -> Both (a) and (r) are true and (r) is the correct reason for (a)


-NA-


Question 12. Match the entries in Group I with the process parameters in Group II.Group I                         Group IIP. Clark electrode    1. Liquid levelQ. Redox probe      2. Dissolved oxygen concentrationR. Load cell              3. Vessel pressureS. Diaphragm gauge  4. pH (anaerobic process)
  1.    P-2, Q-1, R-3, S-4
  2.    P-4, Q-2, R-3, S-1
  3.    P-2, Q-4, R-1, S-3
  4.    P-2, Q-1, R-4, S-3
 Discuss Question
Answer: Option C. -> P-2, Q-4, R-1, S-3


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Question 13. Determine the correctness or otherwise of the following Assertion (a) and Reason (r). Assertion: Cell mass yield of a methylotrophic yeast is more on methanol compared to glucose. Reason: Methanol has a greater degree of reductance compared to glucose.
  1.    Both (a) and (r) are correct and (r) is the correct reason for (a)
  2.    (a) is correct, (r) is false
  3.    (a) is false, (r) is correct
  4.    Both (a) and (r) are correct but (r) is not the correct reason for (a)
 Discuss Question
Answer: Option A. -> Both (a) and (r) are correct and (r) is the correct reason for (a)


-NA-


Question 14. Match the downstream processes in Group I with the products in Group II.Group I                         Group IIP. Solvent extraction   1. Lactic acidQ. Protein-A linked affinity chromatography 2. PenicillinR. Extractive distillation   3. Monoclonal antibodyS. Salting out                 4. Lipase
  1.    P-2, Q-3, R-1, S-4
  2.    P-4, Q-1, R-2, S-3
  3.    P-4, Q-1, R-3, S-2
  4.    P-2, Q-4, R-1, S-3
 Discuss Question
Answer: Option A. -> P-2, Q-3, R-1, S-4


-NA-


Question 15. A disease is inherited by a child with a probability of 1/4. In a family with two children, the
probability that exactly one sibling is affected by this disease is
  1.    1/4
  2.    3/8
  3.    7/16
  4.    9/16
 Discuss Question
Answer: Option B. -> 3/8


-NA-


Question 16. The maximum cell concentration (g l-1) expected in a bioreactor with initial cell concentration of
1.75 g l-1 and an initial glucose concentration of 125 g l-1 is (Yx/s = 0.6 g cell/g substrate) ________
  1.    67.4 to 67.6
  2.    43.4 to 43.6
  3.    87.4 to 87.6
  4.    76.7 to 76.9
 Discuss Question
Answer: Option D. -> 76.7 to 76.9


-NA-


Question 17. A fed batch culture was operated with intermittent addition of glucose solution at a flow rate of
200 ml h-1. The values of Ks, μm and D are 0.3 g l-1, 0.4 h-1 and 0.1 h-1, respectively. Determine the
concentration of growth limiting substrate (gl-1) in the reactor at quasi-steady state. ____________
  1.    0.4
  2.    0.2
  3.    0.1
  4.    0.7
 Discuss Question
Answer: Option C. -> 0.1


-NA-


Question 18. A solution was prepared by dissolving 100 mg of protein X in 100 ml of water. Molecular weight of protein X is 15,000 Da; Avogadro's number = 6.022 * 1023. Calculate the molarity(μM) of the resulting solution.
  1.    66.6
  2.    6.6
  3.    0.67
  4.    0.067
 Discuss Question
Answer: Option A. -> 66.6


-NA-


Question 19. In a factory, two machines M1 and M2 manufacture 60% and 40% of the autocomponents
respectively. Out of the total production, 2% of M1 and 3% of M2 are found to be defective. If a
randomly drawn autocomponent from the combined lot is found defective, what is the probability
that it was manufactured by M2?
  1.    0.35
  2.    0.45
  3.    0.5
  4.    0.4
 Discuss Question
Answer: Option C. -> 0.5


-NA-


Question 20. If |-2X + 9| = 3 then the possible value of |-X| - X2 would be:
  1.    30
  2.    -30
  3.    -42
  4.    42
 Discuss Question
Answer: Option B. -> -30


-NA-


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