Question
Zeroes of x2−56x+108 are______.
Answer: Option A
:
A
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:
A
In a quadratic equation ax2+bx+c,both zeroes are positive when a is positive, b is negative and c is positive.
In this case, x2−56x+108 can be factorized as (x−2)(x−54).
⟹the roots are 2 and 54; both are positive.
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