Question
The zeroes of mn(x2+1)=(m2+n2)x are:
Answer: Option A
:
A
Given polynomial, mn(x2+1)=(m2+n2)x
Let's factorise it.
mnx2−(m2+n2)x+mn=0
⇒mnx2−m2x−n2x+mn=0
⇒mx(nx−m)−n(nx−m)=0
⇒(mx−n)(nx−m)=0
⇒mx−n=0 or nx−m=0
⇒x=mn or nm
So, zeroes of the given polynomial are mn and nm.
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:
A
Given polynomial, mn(x2+1)=(m2+n2)x
Let's factorise it.
mnx2−(m2+n2)x+mn=0
⇒mnx2−m2x−n2x+mn=0
⇒mx(nx−m)−n(nx−m)=0
⇒(mx−n)(nx−m)=0
⇒mx−n=0 or nx−m=0
⇒x=mn or nm
So, zeroes of the given polynomial are mn and nm.
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