Question
Which two are equal?
- 32/4
- (8 >> 2) << 4
- 2^5
- 128 >>> 2
- 2 >> 5
Answer: Option B
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(2) and (4) are correct. (2) and (4) both evaluate to 32. (2) is shifting bits right then left
using the signed bit shifters >>and <<. (4) is shifting bits using the unsigned operator
>>>, but since the beginning number is positive the sign is maintained.
(1) evaluates to 8, (3) looks like 2 to the 5th power, but ^ is the Exclusive OR operator
so (3) evaluates to 7. (5) evaluates to 0 (2 >> 5 is not 2 to the 5th).
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