When KMnO4 acts as an oxidising agent and ultimately forms [MnO4]−2,

Question

When

K M n O_{4}

acts as an oxidising agent and ultimately forms

[M n O_{4}]^{- 2}, M n O_{2}, M n_{2} O_{3}, M n^{+ 2}

then the number of electrons transferred in each case respectively is

Options:

A . 4, 3, 1, 5

B . 1, 5, 3, 7

C . 1, 3, 4, 5

D . 3, 5, 7, 1

Answer: Option C
:
C
This has to be answered based on the oxidation number of the central metal atom in each case.
To start with Mn has +7 oxidation number in

K M n O_{4}

. Likewise, we have

+ 6 M n O_{4}^{2 -}

+ 4 M n O_{2}

+ 3 M n_{2} O_{3}

+ 2 M n^{2 +}

The number of electrons transferred in each case is 1, 3, 4, 5 respectively.

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