Question
#include<stdio.h>
int main()
{
printf("%u %s\n", &"Hello1", &"Hello2");
return 0;
}
What will be the output of the following program in 16 bit platform assuming that
1022 is memory address of the string "Hello1" (in Turbo C under DOS) ?
#include<stdio.h>
int main()
{
printf("%u %s\n", &"Hello1", &"Hello2");
return 0;
}
Answer: Option A
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In printf("%u %s`setminus`n", &"Hello", &"Hello");.
The %u format specifier tells the compiler to print the memory address of the "Hello1".
The %s format specifier tells the compiler to print the string "Hello2".
Hence the output of the program is "1022 Hello2".
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