What will be the output of the program? public class Switch2 { final static short x = 2; public static int y = 0; public static void main(String [] args) { for (int z=0; z { switch (z) { case x: System.out.print("0 "); case x-1: System.out.print("1 "); case x-2: System.out.print("2 "); } } } } Options: A . &nbsp0 1 2 B . &nbsp0 1 2 1 2 2 C . &nbsp2 1 0 1 0 0 D . &nbsp2 1 2 0 1 2

What will be the out

Question

What will be the output of the program?

public class Switch2
{
final static short x = 2;
public static int y = 0;
public static void main(String [] args)
{
for (int z=0; z < 3; z++)
{
switch (z)
{
case x: System.out.print("0 ");
case x-1: System.out.print("1 ");
case x-2: System.out.print("2 ");
}
}
}
}

Options:

A . 0 1 2

B . 0 1 2 1 2 2

C . 2 1 0 1 0 0

D . 2 1 2 0 1 2

Answer: Option D

The case expressions are all legal because x is marked final, which means the

expressions can be evaluated at compile time. In the first iteration of the for loop

case x-2 matches, so 2 is printed. In the second iteration, x-1 is matched so 1

and 2 are printed (remember, once a match is found all remaining statements

are executed until a break statement is encountered). In the third iteration, x

is matched. So 0 1 and 2 are printed.