Question
#include<stdio.h>
int main()
{
int arr[] = {12, 14, 15, 23, 45};
printf("%u, %u\n", arr, &arr);
return 0;
}
What will be the output of the program if the array begins at address 65486?
#include<stdio.h>
int main()
{
int arr[] = {12, 14, 15, 23, 45};
printf("%u, %u\n", arr, &arr);
return 0;
}
Answer: Option B
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Step 1: int arr[] = {12, 14, 15, 23, 45}; The variable arr is declared as an integer
array and initialized.
Step 2: printf("%u, %u`setminus`n", arr, &arr); Here,
The base address of the array is 65486.
=> arr, &arr is pointing to the base address of the array arr.
Hence the output of the program is 65486, 65486
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