Question
#include<stdio.h>
int main()
{
int arr[1]={10};
printf("%d\n", 0[arr]);
return 0;
}
What will be the output of the program ?
#include<stdio.h>
int main()
{
int arr[1]={10};
printf("%d\n", 0[arr]);
return 0;
}
Answer: Option B
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Step 1: int arr[1]={10}; The variable arr[1] is declared as an integer array with size '2'
and it's first element is initialized to value '10'(means arr[0]=10)
Step 2: printf("%d`setminus`n", 0[arr]); It prints the first element value of the variable arr.
Hence the output of the program is 10.
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