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Question


What will be output of the following ?


#include<stdio.h>
#include<math.h>
int main()
{
printf("%f\n", sqrt(36.0));
return 0;
}
Options:
A .  6.0
B .  6
C .  6.0000
D .  Some absurd result
Answer: Option C


printf("%f`setminus`n", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000).



Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the

 given number.




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