Question
int main()
{
float a =5.375;
char *p;
int i;
p = (char*)&a;
for(i=0;i<=3;i++)
printf("%02x", (unsigned char)p[i]);
return 0;
}
If the binary equivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program?
int main()
{
float a =5.375;
char *p;
int i;
p = (char*)&a;
for(i=0;i<=3;i++)
printf("%02x", (unsigned char)p[i]);
return 0;
}
Answer: Option C
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