Question
What was the day of the week on 28th May, 2006?
Answer: Option D
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
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28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) \(\equiv\) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
So,
148 days = (21 weeks + 1 day) 
1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
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