Question
What should be the value of a, if the value of 2x2+6a–5x+10 is 25, when x = 1?
Answer: Option B
:
B
Given,2x2+6a–5x+10=25
Substituting the value of x = 1 in the above equation, we get,
2(1)2+6a−5(1)+10=25
⇒ 2 + 6a - 5 + 10 = 25
⇒ 6a + 7 = 25
⇒ 6a = 25 - 7 = 18
⇒ a = 3
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:
B
Given,2x2+6a–5x+10=25
Substituting the value of x = 1 in the above equation, we get,
2(1)2+6a−5(1)+10=25
⇒ 2 + 6a - 5 + 10 = 25
⇒ 6a + 7 = 25
⇒ 6a = 25 - 7 = 18
⇒ a = 3
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