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What is the output of this C code(when 1 is entered)?

    void main()

    {

        double ch;

        printf("enter a value btw 1 to 2:");

       scanf("%lf", &ch);

        switch (ch)

        {

        case 1:

            printf("1");

            break;

        case 2:

            printf("2");

            break;

        }

    }

Options:
A .  Compile time error
B .  1
C .  2
D .  Varies
Answer: Option A


none



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