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What is the output of this C code(When 1 is entered)?

    void main()

    {

       char *ch;

       printf("enter a value btw 1 to 3:");

        scanf("%s", ch);

       switch (ch)

        {

        case "1":

            printf("1");

            break;

        case "2":

            printf("2");

            break;

        }

    }

Options:
A .  1
B .  Compile time error
C .  2
D .  Run time error
Answer: Option B


none



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