Answer: Option A
:
A
Look at the carbon where stereochemical data is given.
Now, we need to figure out if there are any elements of symmetry.
If we draw a plane that passes through this carbonand $-H$ and $-NH2$,
we don't get two equal halves. One one side, $C{H}_{3}C{H}_{2}CO$ and on the
other side we have $C{H}_{3}CHClCO$.
Hence the center is stereogenic. Also, since there are no elements of symmetry,
this molecule is definitely chiral!