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Question


Add the following:
 (i) 5a2b2+10ab12a2+15b20 and 34ab+24a2+22b+24
 (ii) abc+6bcd+abd9ab+4bc9a43 and 4acd+10ac54b32c
 (iii) 5bc+9ad3c12 and 245c5b+2ab  [4 MARKS]


Options:
Answer: Option A
:

Concept: 1 Mark
Application: 1 Mark each
(i) 5a2b2+10ab12a2+15b20+34ab+24a2+22b+24

    =5a2b2+44ab+12a2+37b+4
(ii) abc+6bcd+abd9ab+4bc9a43+4acd+10ac54b32c
    =abc+6bcd+abd9ab+4bc9a43+4acd+10ac54b32c
(iii) 5bc+9ad3c12+245c5b+2ab
    =5bc+9ad8c+125b+2ab



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