Two wires of the same material and length are stretched by the same force. Their

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Two wires of the same material and length are stretched by the same force. Their masses are in the ratio 3:2. Their elongations are in the ratio

Options:

A . 3 : 2

B . 9 : 4

C . 2 : 3

D . 4 : 9

Answer: Option C
:
C

Y = \frac{F l}{A △ l} o r △ l \propto \frac{1}{A}

Again,

m = A l p, m \propto A

△ l \propto \frac{1}{m}

Therefore

\frac{△ l_{1}}{△ l_{2}} = \frac{m_{2}}{m_{1}} = \frac{2}{3}

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