Question
A wire extends by 1 mm when a force is applied. Double the force is applied to another wire of same material and length but half the radius of cross section. The elongation of the wire in mm will be
Answer: Option A
:
A
Y=FlA△lor△l∝Fr2
or △l2△l1=F2F1×r21r22
or △l2△l1=2×2×2=8
or △l2=8△l1=8×1=8 mm
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:
A
Y=FlA△lor△l∝Fr2
or △l2△l1=F2F1×r21r22
or △l2△l1=2×2×2=8
or △l2=8△l1=8×1=8 mm
Was this answer helpful ?
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