Two students appeared at an examination. One of them secured 9 marks more than t

Question

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

Options:

A . 39, 30

B . 41, 32

C . 42, 33

D . 43, 34

Answer: Option C

Let their marks be (x + 9) and x.

Then, x + 9 = \(\frac{56}{100}\left(x+9+x\right)\)

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

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