Two metal spheres of radii in the ratio 3:4 are connected and a charge of 14

Question

μ

C is given to the system and then they are separated so that there is no mutual force between them. The potential due to the larger sphere at a distance of 3m from the centre of the sphere is

Options:

A . 72KV

B . 36KV

C . 24KV

D . 12KV

Answer: Option C
:
C

q_{1} + q_{2} = 14 μ C . . . (1) V = \frac{q_{1}}{c_{1}} = \frac{q_{2}}{c_{2}}; \frac{q_{1}}{q_{2}} = \frac{4 π ϵ_{0} r_{1}}{4 π ϵ_{0} r_{2}}; \frac{q_{1}}{q_{2}} = \frac{r_{1}}{r_{2}} = \frac{3}{4} q_{1} = 6 μ C; q_{2} = 8 μ C V_{2} = \frac{1}{4 π ϵ_{0}} \frac{q_{2}}{r} = 9 \times 10^{9} \times \frac{8 \times 10^{- 6}}{3} V_{2} = 24 \times 10^{3} V

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