Question
Four identical charges +50 μC each are placed, one at each corner of a square of side 2m. How much external energy is required to bring another charge of +50 μC from infinity to the centre of the square (Given 14πϵ0=9×109 Nm2C2)
Answer: Option A
:
A
Potential at the centre of square
V=4×(9×109×50×10−6√2)=90√2×104V
Work done in bringing a charge (q = 50μC) from ∞ to centre (O) of the square is
W=q(V0−V∞)=qV0
⇒W=50×10−6×90√2×104=64J
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:
A
Potential at the centre of square
V=4×(9×109×50×10−6√2)=90√2×104V
Work done in bringing a charge (q = 50μC) from ∞ to centre (O) of the square is
W=q(V0−V∞)=qV0
⇒W=50×10−6×90√2×104=64J
Was this answer helpful ?
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