Question
There are 5 tasks and 5 persons, Task 1 cannot be assigned to either person 1 or person 2, Task 2 must be assigned to either person-3 or person-4 every person is to be assigned one task, In how many ways can the assignment be done?
Answer: Option C
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Task 2 must be assigned to P4 or P3 =2C1
For task 1 only 2 persons i.e.., P3 or P4and P5 = 2C1
Task 3 only 3 person available =3C1
For task 4 only 2 persons available =2C1
For task 5 only 1 person left = 1
Therefore, total number of ways
= 2C1 x 2C1x 3C1x 2C1 x1
= 2x2x3x2x1 =24
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