Question
The solution of the pair of linear equations
x+2y=5 and 7x+3y=13 is (2, 1).
x+2y=5 and 7x+3y=13 is (2, 1).
Answer: Option B
:
B
x+2y=5 ...(1)
7x+3y=13 ...(2)
Let's solve these equations using elimination method.
Onmultiplying the first equation by 7, we get
7x+14y=35 ...(3)
On subtracting (2) from (3), we have
7x+14y=35
−7x−3y=−13
_______________
11y=22
⇒y=2
On subsituting value of y inx+2y=5, we get
x+2(2)=5
⇒x=1
⇒x=1andy=2
Hence, the solution of the given equations is (1, 2).
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B
x+2y=5 ...(1)
7x+3y=13 ...(2)
Let's solve these equations using elimination method.
Onmultiplying the first equation by 7, we get
7x+14y=35 ...(3)
On subtracting (2) from (3), we have
7x+14y=35
−7x−3y=−13
_______________
11y=22
⇒y=2
On subsituting value of y inx+2y=5, we get
x+2(2)=5
⇒x=1
⇒x=1andy=2
Hence, the solution of the given equations is (1, 2).
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