Question
A man starts his job with a certain salary and earns a fixed increment every year. If his salary was ₹ 15000 after 4 years of service and ₹ 18000 after 10 years of service, then find his starting salary and annual increment respectively.
Answer: Option B
:
B
Let starting salary be ₹x
and annual increment be ₹ y
According to the first condition:
x + 4y = 15000 ......(i)
According to the second condition:
x + 10y = 18000 ......(ii)
Subtracting (i) from (ii), we get
6y = 3000
y = 500
Substituiting y = 500 in equation (i), we get
x + (4×500) = 15000
x = 15000 - 2000
x = 13000
Hence starting salary is ₹ 13000 and annual increment is ₹ 500.
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:
B
Let starting salary be ₹x
and annual increment be ₹ y
According to the first condition:
x + 4y = 15000 ......(i)
According to the second condition:
x + 10y = 18000 ......(ii)
Subtracting (i) from (ii), we get
6y = 3000
y = 500
Substituiting y = 500 in equation (i), we get
x + (4×500) = 15000
x = 15000 - 2000
x = 13000
Hence starting salary is ₹ 13000 and annual increment is ₹ 500.
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