Question
If the numerator of a fraction is increased by 2 and its denominator is decreased by 1, it becomes 23. If the numerator is increased by 1 and the denominator is increased by 2, it becomes 13. Find the fraction.
Answer: Option A
:
A
Let the fraction be xy
∴x+2y−1=23andx+1y+2=13
⇒3x−2y=−8....(i)
and3x−y=−1......(ii)
⇒3x−2y=−8
−(3x−y=−1)
⇒3x−2y=−8
−3x+y=1
______________________
−y=−7
______________________
⇒y=7
Substitutingy = 7 in equation (ii), we get
3x−(14)=−8
3x=−8+14=6
∴x=2
⇒x=2andy=7
Was this answer helpful ?
:
A
Let the fraction be xy
∴x+2y−1=23andx+1y+2=13
⇒3x−2y=−8....(i)
and3x−y=−1......(ii)
⇒3x−2y=−8
−(3x−y=−1)
⇒3x−2y=−8
−3x+y=1
______________________
−y=−7
______________________
⇒y=7
Substitutingy = 7 in equation (ii), we get
3x−(14)=−8
3x=−8+14=6
∴x=2
⇒x=2andy=7
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution