Question
The solution of (y(1+x−1)+siny)dx+(x+logx+x cosy)dy=0 is
Answer: Option C
:
C
The given equation can be written as y(1+x−1)dx+(x+logx)dy+sinydx+xcosydy=0
⇒d(y(x+logx))+d(xsiny)=0→y(x+logx)+xsiny=C
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:
C
The given equation can be written as y(1+x−1)dx+(x+logx)dy+sinydx+xcosydy=0
⇒d(y(x+logx))+d(xsiny)=0→y(x+logx)+xsiny=C
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