Question
The ratio of the weights of Meenakshi to that of her friend Ankur is 13:15. Ankur now starts to exercise daily and loses 5 kg, and now the ratio of their weights is 13:14. How much does Ankur weigh now?
Answer:
:
Concept: 1 Mark
Application: 1 Mark
Steps: 1 Mark
Solution: 1 Mark
Let x and y be the weight of Meenakshi and Ankur has respectively.
The ratio of the weights of Meenakshi to Ankur = 13:15
After exercising, ratio of the weights of Meenakshi to Ankur = x :( y-5) = 13:14
Comparing bothxy =1315andxy−5 =1314 we get,
⇒13y=15x..............(i) and
14x=13(y−5)
⇒14x=13y−65............(ii)
Substituting the value of (i) in (ii) we get,
⇒14x=15x−65.
x=65
Substitute the value of x in (i)
⇒13y=15×65
y=15×5=75
But Ankur lost 5 kg
∴ Ankur'spresent weight is (y−5)=(75−5)=70kg
Was this answer helpful ?
:
Concept: 1 Mark
Application: 1 Mark
Steps: 1 Mark
Solution: 1 Mark
Let x and y be the weight of Meenakshi and Ankur has respectively.
The ratio of the weights of Meenakshi to Ankur = 13:15
After exercising, ratio of the weights of Meenakshi to Ankur = x :( y-5) = 13:14
Comparing bothxy =1315andxy−5 =1314 we get,
⇒13y=15x..............(i) and
14x=13(y−5)
⇒14x=13y−65............(ii)
Substituting the value of (i) in (ii) we get,
⇒14x=15x−65.
x=65
Substitute the value of x in (i)
⇒13y=15×65
y=15×5=75
But Ankur lost 5 kg
∴ Ankur'spresent weight is (y−5)=(75−5)=70kg
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