The negation of the statement ( p ∨ ∼ q ) ∧ q is Options: A . &nbsp ( ∼ p ∨ q ) ∧ ∼ q B . &nbsp ( p ∧ ∼ q ) ∨ q C . &nbsp ( ∼ p ∧ q ) ∨ ∼ q D . &nbsp ( p ∧ ∼ q ) ∨ ∼ q

Answer: Option C : C ∼ ( ( p ∨ ∼ q ) ∧ q ) = ∼ ( p ∨ ∼ q ) ∨ ∼ q = ( ∼ p ∧ q ) ∨ ∼ q

The negation of the statement (p ∨∼q)∧q is

Question

The negation of the statement $(p \lor \sim q) \land q$ is

Options:

A .

(\sim p \lor q) \land \sim q

B .

(p \land \sim q) \lor q

C .

(\sim p \land q) \lor \sim q

D .

(p \land \sim q) \lor \sim q

Answer: Option C
:
C

$\sim ((p \lor \sim q) \land q) =\sim (p \lor \sim q) \lor \sim q = (\sim p \land q) \lor \sim q$

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