Question
The mark distribution of 40 students in an exam is shown below. Find the standard deviation of the distribution.
Marks0−1010−2020−3030−4040−50No. of Students7101265
Answer: Option B
:
B
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B
XFFXD=X−¯XD2FD25735−1832422681510150−8646402512300244835621012144864455225224842420∑F=40∑FX=920∑FD2=6240
Mean, ¯X=∑FX∑F=92040=23
σ=√∑FD2∑F=√624040=√156=12.49
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