Question
The diameter of a brass wire is 0.6 mm and Y is 9 ×106 N m−2.The force which will increase its length by 0.2% is about
Answer: Option B
:
B
F=YA△ll
=9×1010×227×(0.6×10−3)24×0.2100N =51 N approx
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:
B
F=YA△ll
=9×1010×227×(0.6×10−3)24×0.2100N =51 N approx
Was this answer helpful ?
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