Question
When a certain weight is suspended from a long uniform wire, its length increases by one cm. If the same weight is suspended from another wire of the same material and length but having a diameter half of the first one then the increase in length will be -
Answer: Option C
:
C
c):I=FLAY⇒l∝1r2 (F,L and Y are constant)
l2l1=(r1r2)2=(2)2=4
⇒l2=4l1=4cm
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:
C
c):I=FLAY⇒l∝1r2 (F,L and Y are constant)
l2l1=(r1r2)2=(2)2=4
⇒l2=4l1=4cm
Was this answer helpful ?
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